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(F)=3F^2+9F+50
We move all terms to the left:
(F)-(3F^2+9F+50)=0
We get rid of parentheses
-3F^2+F-9F-50=0
We add all the numbers together, and all the variables
-3F^2-8F-50=0
a = -3; b = -8; c = -50;
Δ = b2-4ac
Δ = -82-4·(-3)·(-50)
Δ = -536
Delta is less than zero, so there is no solution for the equation
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